0=164t-16t^2

Solution for 0=164t-16t^2 equation:

0=164t-16t^2

We move all terms to the left:

0-(164t-16t^2)=0

We add all the numbers together, and all the variables

-(164t-16t^2)=0

We get rid of parentheses

16t^2-164t=0

a = 16; b = -164; c = 0;
Δ = b2-4ac
Δ = -1642-4·16·0
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26896}=164$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-164)-164}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-164)+164}{2*16}=\frac{328}{32}
=10+1/4
$